# What is the slope-intercept form of the linear equation 2x - 8y = 32?

**Solution:**

The slope and intercept form of a linear equation or a straight line is given by the expression:

y = mx + c

Where the slope is m and c is the intercept.

If (x_{1}, y_{1}) and (x_{2}, y_{2}) are two points on the straight line then the slope m can be calculated as:

m = (y_{2} - y_{1})/(x_{2} - x_{1})

The equation of the line is formed by either of the two expressions below:

(y - y_{1}) = m (x - x_{1})

Or

(y - y_{2}) = m (x - x_{2})

The given equation i.e. 2x - 8y = 32 can be written in the desired format as:

8y = 2x - 32

y = (2/8)x - 32/8

y = (1/4)x - 4

Where, m = slope = 1/4, intercept = -4

## What is the slope-intercept form of the linear equation 2x - 8y = 32?

**Summary:**

The slope-intercept form of the linear equation 2x - 8y = 32 is y = (1/4)x - 4

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