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Working out Memory Size

Started by AMSDOS, 11:08, 16 August 10

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AMSDOS

I was trying to ask myself why a 320x200 resolution doesn't necessarily equate to 64k because a CPC only has roughly a 17k Screen. 320x200 gives me a figure of 64000 then I multiply that by 2 bits because that's the requirement for the amount of colours on a CPC it's 4 which gives me a figure of 128000, but then if I divide this by 8 I get 16000! But the book doesn't explain where they get the figure of 8 from! Anyone know??  :-[
* Using the old Amstrad Languages :D   * with the Firmware :P
* I also like to problem solve code in BASIC :)   * And type-in Type-Ins! :D

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steve

The unit of memory is called a byte, a byte is 8 bits, so you divide the number of bits (128000) by 8 to give you the number of bytes used to store the data.

AMSDOS

* Using the old Amstrad Languages :D   * with the Firmware :P
* I also like to problem solve code in BASIC :)   * And type-in Type-Ins! :D

Home Computing Weekly Programs
Popular Computing Weekly Programs
Your Computer Programs
Updated Other Program Links on Profile Page (Update April 16/15 phew!)
Programs for Turbo Pascal 3

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